Composite Functions
Given f(x) and g(x), we have:
Adding: (f+g)(x) = f(x) + g(x)
Subtracting: (f-g)(x) = f(x) - g(x)
Multiplying: (f.g)(x) = f(x) . g(x)
Dividing: (f/g)(x) = [f(x)]/[g(x)]
Substitution: (f˚g)(x) = f(x)˚g(x) = f(g(x))
Example:
f(x) = x^2 + 1 and g(x) = x-1
(f+g)(x) = x^2 + 1 + x - 1 = x^2 + x
(f-g)(x) = x^2 + 1 - (x-1) = x^2 - x + 2
(f.g)(x) = (x^2+1)(x-1)= x^3 - x^2 + x - 1
(f/g)(x) = (x^2+1)/(x-1)
(f˚g)(x) = f(g(x)) = f(x-1) = (x-1)^2 + 1
Inverse Functions
Two functions are defined as inverses if the compositions f(g(x))=x and g(f(x))=x are true.
Two ways to find inverse functions:
1. Graph the function, then reflect it into y=x to get the graph of the inverse function.
2. Switch the x's for y's and the y's for x's in the function, solve for y to get the inverse function.
Showing posts with label math. Show all posts
Showing posts with label math. Show all posts
Friday, March 11, 2011
Friday, January 14, 2011
Special Triangles
Since it seems as if most of you are having trouble with special triangles, here's an easy (somewhat, but anyways, suck it up) formula.
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